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This question belongs to Arithmetic Ability Number System
Number System
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Let N = 1421 × 1423 × 1425. What is the remainder when N is divided by 12?

Answer & Solution
Correct Answer: Option C
Remainder,
$$\eqalign{ & \frac{{1421 \times 1423 \times 1425}}{{12}} = R \cr & R \Rightarrow \frac{{5 \times 7 \times 9}}{{12}} \cr} $$

[Here, we have taken individual remainder such as 1421 divided by 12 gives remainder 5, 1423 and 1425 gives the remainder as 7 and 9 on dividing by 12.]

Now, the sum is reduced to,
$$\frac{{5 \times 7 \times 9}}{{12}} = \frac{{35 \times 9}}{{12}}$$
$$\frac{{35 \times 9}}{{12}}$$  = Remainder ⇒ -1 × -3 = 3 [Here, we have taken negative remainder.] So, required remainder will be 3.

Note: When, $$\frac{9}{{12}}$$ it gives positive remainder as 9 and it also give a negative remainder -3. As per our convenience,we can take any time positive or negative remainder.
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6 Comments
Harish Sheernam
Harish Sheernam 3 years ago
Why we can taking individual remainders
Prem Mutthalkar
Prem Mutthalkar 5 years ago
Why second option is not correct✅
বিনিদ্র হাসিব
বিনিদ্র হাসিব 6 years ago
Guys suggest me a book for aptitude test preparation
Shahid Ansari
Shahid Ansari 6 years ago
We can just multiplying of the last digit 1×3×5 then divided by 12 to get remainder 3
Kumar Chandan
Kumar Chandan 10 years ago
See, we can take Positive or negative remainder in the shake of simplicity.
Bishnu Chetia
Bishnu Chetia 10 years ago
Why are we taking negative remainder?