94 is divided into two parts in such a way that fifth part of the first and the eighth part of the second are in the ratio 3 : 4. The first part is = ?
A. 30
B. 36
C. 40
D. 28
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & {\text{A}} + {\text{B}} = 94 \cr & \therefore \frac{{\text{A}}}{5}:\frac{{\text{B}}}{8} = 3:4 \cr & \Rightarrow \frac{{{\text{A}} \times 8}}{{5 \times {\text{B}}}} = \frac{3}{4} \cr & \Rightarrow \frac{{\text{A}}}{{\text{B}}} = \frac{3}{4} \times \frac{5}{8} \cr & \Rightarrow \frac{{\text{A}}}{{\text{B}}} = \frac{{15}}{{32}} \cr & {\text{ A}}:{\text{B}} \cr & {\text{ }}15:32 \cr & {\text{Let }}15x:32x \cr & \therefore 15x + 32x = 47x \cr & \Rightarrow 47x = 94 \cr & \Rightarrow x = 2 \cr & \therefore {\text{A}} = 2 \times 15 = 30 \cr & {\text{B}} = 32 \times 2 = 64 \cr} $$Related Questions on Ratio
If a : b : c = 3 : 4 : 7, then the ratio (a + b + c) : c is equal to
A. 2 : 1
B. 14 : 3
C. 7 : 2
D. 1 : 2
If $$\frac{2}{3}$$ of A=75% of B = 0.6 of C, then A : B : C is
A. 2 : 3 : 3
B. 3 : 4 : 5
C. 4 : 5 : 6
D. 9 : 8 : 10
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