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A 12 V source has an internal resistance of 90 Ω. If a load resistance of 20 Ω is connected to the voltage source, the load power, PL, is

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Correct Answer: Option C
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2 Comments
Afifa A
Afifa A 3 years ago
By Voltage divider rule
VL = (Vs * Rs)/ sum of resistances
= (12*20)/ (20+90) = 2.18V
To find power
P = V^2/R
PL = (VL^2)/RL
PL = (2.18^2)/20 = 237.62 mW => 238 mW
Engr Farman
Engr Farman 6 years ago
P=sq I . R