A 220 Ω resistor dissipates 3 W. The voltage is
A. 73.3 V
B. 2.5 V
C. 25.7 V
D. 257 V
Answer: Option C
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A. 73.3 V
B. 2.5 V
C. 25.7 V
D. 257 V
Answer: Option C
This Question Belongs to Electrical Engineering >> Energy And Power
P=v^2/R
P=VI
Since, I=V/R
Therefore, P=V*V/R=V^2/R
Putting P=3 W & R=220 ohm
3=V^2/220
V^2=3*220=660
V=25.67=25.70 V
P=(V^2)/R
(V^2)=P*R
(V^2)=3*220=660
V=25.69=25.7
P=(V^2)/R
3=(V^2)/220
(V^2)=660
V=25.69=25.7