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A 3 ohm resistor having 2 A current will dissipate the power of

A. 2 watts

B. 4 watts

C. 6 watts

D. 8 watts

E. 12 watts

Answer: Option E

Solution (By Examveda Team)

Explanation:

The power dissipated by a resistor is given by the formula:
\( P = I^2 \times R \), where
\( P \) = Power in watts,
\( I \) = Current in amperes,
\( R \) = Resistance in ohms.

Given:
Current, \( I = 2 \, A \)
Resistance, \( R = 3 \, \Omega \)

Calculating power:
\( P = (2)^2 \times 3 = 4 \times 3 = 12 \, \text{watts} \)

Hence, the power dissipated is 12 watts.

Therefore, the correct answer is Option E: 12 watts.

This Question Belongs to Electrical Engineering >> Current Electricity

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Comments (7)

  1. Dinesh Datalkar
    Dinesh Datalkar:
    6 months ago

    R-3Ohm
    I-3Amp
    P-?
    P=I²R
    P=2²×3
    P=12Watt

  2. Awais Ahmed
    Awais Ahmed:
    1 year ago

    Answer and Explanation:
    P = i 2 R . Thus, the power dissipated in the given resistance is 12 Watts.

  3. Eric Asiedu
    Eric Asiedu:
    4 years ago

    Wrong answer.. 12W is the answer
    Solution: V=IR. V = 2×3 =6
    And P= V²/R. 6²/3 = 12W

  4. Pradeep Bijarniya
    Pradeep Bijarniya:
    5 years ago

    Power Dissipation = I*2R=12w

  5. Gurpreet Singh
    Gurpreet Singh:
    6 years ago

    Wrong answer, the answer is 12 W,
    Solñ: V=IR. V= 2 x 3 = 6 volts
    P=VI. P= 6 x 2 = 12 watts

  6. ZERO
    ZERO :
    7 years ago

    P=I^2R

  7. Md Tarif
    Md Tarif:
    7 years ago

    Wrong answer.right answer is 12.that are not in below options

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