A 3 ohm resistor having 2 A current will dissipate the power of
A. 2 watts
B. 4 watts
C. 6 watts
D. 8 watts
E. 12 watts
Answer: Option E
Solution (By Examveda Team)
Explanation:The power dissipated by a resistor is given by the formula:
\( P = I^2 \times R \), where
\( P \) = Power in watts,
\( I \) = Current in amperes,
\( R \) = Resistance in ohms.
Given:
Current, \( I = 2 \, A \)
Resistance, \( R = 3 \, \Omega \)
Calculating power:
\( P = (2)^2 \times 3 = 4 \times 3 = 12 \, \text{watts} \)
Hence, the power dissipated is 12 watts.
Therefore, the correct answer is Option E: 12 watts.
This Question Belongs to Electrical Engineering >> Current Electricity
R-3Ohm
I-3Amp
P-?
P=I²R
P=2²×3
P=12Watt
Answer and Explanation:
P = i 2 R . Thus, the power dissipated in the given resistance is 12 Watts.
Wrong answer.. 12W is the answer
Solution: V=IR. V = 2×3 =6
And P= V²/R. 6²/3 = 12W
Power Dissipation = I*2R=12w
Wrong answer, the answer is 12 W,
Solñ: V=IR. V= 2 x 3 = 6 volts
P=VI. P= 6 x 2 = 12 watts
P=I^2R
Wrong answer.right answer is 12.that are not in below options