A 3.3 kΩ resistor dissipates 0.25 W. The current is
A. 8.7 mA
B. 87 mA
C. 8.7 µA
D. 8.7 A
Answer: Option A
This Question Belongs to Electrical Engineering >> Energy And Power
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Solution
Power loss in a resistor (P) =I2.R
Where, I is the current
R is the resistance
P is the power loss. Always power loss in a resistor takes place in the form of heat energy.
Given Resistance = 3.3 KΩ
Power loss = 0.25 Watt
0.25=I2×3300
Current i=√(0.25/3300)=8.7 mA