A 6 V battery output is divided down to obtain two output voltages. Three 2.2 kΩ resistors are used to provide the two taps. The two output voltages are
A. 2 V, 4 V
B. 2 V, 2 V
C. 2 V, 6 V
D. 4 V, 6 V
Answer: Option A
Solution(By Examveda Team)
Imagine the three 2.2 kΩ resistors connected one after another, forming a series circuit.The 6V battery is connected across this entire series.
The voltage drops across resistors in a series are proportional to their resistance. Since all resistors have the same resistance, the voltage will be divided equally.
Calculating the voltage drop across each resistor:
Since there are three equal resistors, the 6V will be divided into three equal parts.
6V / 3 = 2V per resistor.
Finding the output voltages:
The first tap is after the first resistor. Thus, the voltage at the first tap with respect to ground is the voltage drop across that resistor, which is 2V.
The second tap is after the second resistor. Therefore, the voltage at the second tap with respect to ground is the sum of the voltage drops across the first two resistors. That means 2V + 2V = 4V.
Therefore, the two output voltages are 2V and 4V.
The Correct Answer is Option A: 2 V, 4 V.
This Question Belongs to Electrical Engineering >> Series Parallel Circuits
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