A 68 Ω resistor is connected across the terminals of a 3 V battery. The power dissipation of the resistor is
A. 132 mW
B. 13.2 mW
C. 22.6 mW
D. 226 mW
Answer: Option A
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Power = (V)^2/R.
Power = (3*3)/68 = 9/68 = 0.132Watts.
Or 0.132*1000 = 132 mWatts.