A and B working together completed a job in 5 days. If A works twice as efficiently as he actually did and B works $$\frac{1}{3}$$ of actual efficiency, the work would have completed in 3 days. Find the for A to complete the job alone.
A. $$6\frac{1}{2}$$
B. $$6\frac{1}{4}$$
C. $$6\frac{3}{4}$$
D. $$12\frac{1}{2}$$
E. None of these
Answer: Option B
Solution (By Examveda Team)
One Day's work of A and B together, $$\frac{1}{{\text{A}}} + \frac{1}{{\text{B}}} = \frac{1}{5}\,........({\text{i}})$$ When A works with twice efficiency,Then, $$\frac{2}{{\text{A}}} + \frac{1}{{3{\text{B}}}} = \frac{1}{3}\,........({\text{ii}})$$ on solving equations (i) and (ii), we get $$A = \frac{{25}}{4} = 6\frac{1}{4}$$This Question Belongs to Arithmetic Ability >> Time And Work
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Comments (2)
Related Questions on Time and Work
A. 18 days
B. 24 days
C. 30 days
D. 40 days
From my calculation this ans is "D" not B
thank u.