A bag contains 10 mangoes out of which 4 are rotten, two mangoes are taken out together. If one of them is found to be good, the probability that other also good is-
A. $$\frac{1}{3}$$
B. $$\frac{8}{15}$$
C. $$\frac{5}{18}$$
D. $$\frac{2}{3}$$
Answer: Option A
Solution(By Examveda Team)
Out of mangoes, 4 mangoes are rotten∴ Required probability
$$\eqalign{ & = \frac{{{}^6{C_2}}}{{{}^{10}{C_2}}} \cr & = \frac{{\frac{{6!}}{{2!\left( {6 - 2} \right)!}}}}{{\frac{{10!}}{{2!\left( {10 - 2} \right)!}}}} \cr & = \frac{{\frac{{6!}}{{2!4!}}}}{{\frac{{10!}}{{2! \times 8!}}}} \cr & = \frac{{\frac{{6 \times 5}}{{1 \times 2}}}}{{\frac{{10 \times 9}}{{1 \times 2}}}} \cr & = \frac{{6 \times 5}}{{10 \times 9}} \cr & = \frac{1}{3} \cr} $$
This Question Belongs to Arithmetic Ability >> Probability
Join The Discussion
Comments ( 1 )
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
Here , ¹⁰c₂ = (10*9)/(2*1) = 45
and , ⁽¹⁰⁻⁴⁾c₂ = (6*5)/(2*1) = 15
So , P(g) = 15/45 i.e. 1/3