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What is the probability of getting a sum 9 from two throws of a dice?
Answer & Solution
Correct Answer:
Option
C
In two throws of a dice, n(S) = (6 x 6) = 36
Let E = event of getting a sum
= {(3, 6), (4, 5), (5, 4), (6, 3)}
$$\eqalign{ & \therefore P\left( E \right) = \frac{{n\left( E \right)}}{{n\left( S \right)}} \cr & = \frac{4}{{36}}\cr & = \frac{1}{9} \cr} $$
Let E = event of getting a sum
= {(3, 6), (4, 5), (5, 4), (6, 3)}
$$\eqalign{ & \therefore P\left( E \right) = \frac{{n\left( E \right)}}{{n\left( S \right)}} \cr & = \frac{4}{{36}}\cr & = \frac{1}{9} \cr} $$
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