A bag contains five white and four red balls. Two balls are picked at random from the bag. What is the probability that they both are different color?
A. $$\frac{{4}}{{9}}$$
B. $$\frac{{5}}{{9}}$$
C. $$\frac{{7}}{{9}}$$
D. $$\frac{{8}}{{9}}$$
Answer: Option B
Solution(By Examveda Team)
Two balls can be picked from nine balls in $${{}^9{C_2}}$$ ways.We select one white ball and one red ball from five white balls and four red balls.
This can be done $${{}^5{C_1}}$$ . $${{}^4{C_1}}$$ ways.
∴ The required probability
$$\eqalign{ & = \frac{{5 \times 4}}{{{}^9{C_2}}} \cr & = \frac{{20}}{{36}} \cr & = \frac{5}{9} \cr} $$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
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