A bar of length ‘L’ meters extends by ‘$$l$$’ mm under a tensile force of ‘P’. The strain produced in the bar is
A. $$\frac{l}{{\text{L}}}$$
B. 0.1 $$\frac{l}{{\text{L}}}$$
C. 0.01 $$\frac{l}{{\text{L}}}$$
D. 0.001 $$\frac{l}{{\text{L}}}$$
Answer: Option D
l/L= m/mm= 1/1000L= 0.001/L