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A body having moment of inertia of 30 kg m2 is rotating at 210 RPM and mashes with another body at rest having M.I. of 40 kg m2. The resultant speed after meshing will be

A. 90 RPM

B. 100 RPM

C. 80 RPM

D. None of the mentioned

Answer: Option A


This Question Belongs to Mechanical Engineering >> Theory Of Machine

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Comments (3)

  1. Zain Abideen
    Zain Abideen:
    2 years ago

    Solution: Given,
    Moment of inertia of first body (I1) = 30 kg m^2
    Rotational speed of first body (ω1) = 210 RPM
    Moment of inertia of second body at rest (I2) = 40 kg m^2
    To find: Resultant speed after meshing Formula:
    Conservation of Angular Momentum: I1ω1 = (I1+I2)ω2
    where, ω2 = Resultant speed after meshing
    Calculation: Substituting the given values in the formula, we get
    30 × 210 = (30 + 40) × ω2 ω2 = (30 × 210) / (30 + 40) ω2 = 90 RPM
    Therefore, the resultant speed after meshing is 90 RPM.

  2. Vivek Raj
    Vivek Raj:
    3 years ago

    Wrong answer 157.5 right answer

  3. Hanif Jan
    Hanif Jan:
    5 years ago

    how to solve it.. any one

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