A body moves, from rest with a constant acceleration of 5 m per sec. The distance covered in 5 sec is most nearly

@infinite knowledge sol#
Body start from rest means "Initial velocity is zero".The body start moving with acceleration 5 meter/sec.how much distance covered by body in 5 sec ?
Initial velocity is represnted by " vi"=0
time is "t". T=5
acceleration is "a"=5
distance is "s".
so, formula for distance according to question is
S=Vi×t+1/2at^2
S=0×5+1/2×5×5^2
S=0+1/2×5×25
S=0+1/2×125
S=0+0.5×125
S=62.5 and.

Body starts from rest u=0
time = 5sec
acc = 5m/s^2
s=ut+1/2at^2
s= 0+(5*(5*5))/2=125/2=62.5m

Please explain how?

@infinite knowledge use below formula

s=ut+1/2at^2

where u =0 m/s
t = 5 sec
a = 5m/s^2

Why the answer is B