A body of 4.0 kg is lying at rest. Under the action of a constant force, it gains a speed of 5 m/s. The work done by the force will be ________
A. 50 J
B. 30 J
C. 20 J
D. 40 J
Answer: Option A
Solution (By Examveda Team)
Work done = 1/2*m*V2=1/2*4*52
= 1/2*4*25
= 2*25
= 50 J
Join The Discussion