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A box contains 4 red, 5 green and 6 white balls. A ball is drawn at random from the box. What is the probability that the ball drawn is either red or green ?
Answer & Solution
Correct Answer:
Option
B
Total number of balls = (4 + 5 + 6) = 15
P (drawing a red ball or a green ball) = P (red) + P (green)
$$\eqalign{ & = \left( {\frac{4}{{15}} + \frac{5}{{15}}} \right) \cr & = \frac{9}{{15}} \cr & = \frac{3}{5} \cr} $$
P (drawing a red ball or a green ball) = P (red) + P (green)
$$\eqalign{ & = \left( {\frac{4}{{15}} + \frac{5}{{15}}} \right) \cr & = \frac{9}{{15}} \cr & = \frac{3}{5} \cr} $$
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