A box contains 6 white, 2 black and 3 red balls. If a ball is drawn at random, what is the probability that it will not be white?
A. $$\frac{5}{{11}}$$
B. $$\frac{6}{{11}}$$
C. $$\frac{5}{9}$$
D. $$\frac{6}{5}$$
Answer: Option A
Solution (By Examveda Team)
Total balls ⇒ 6 + 2 + 3 = 11 balls$$\eqalign{ & P\left( W \right) = \frac{6}{{11}} \cr & P\left( {{\text{not white ball}}} \right) = 1 - \frac{6}{{11}} = \frac{5}{{11}} \cr} $$
This Question Belongs to Arithmetic Ability >> Probability
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