A box has 6 black, 4 red, 2 white and 3 blue shirts. What is probability of picking at least 1 red shirt in 4 shirts that are randomly picked?
A. $$\frac{{4}}{{15}}$$
B. $$\frac{{24}}{{455}}$$
C. $$\frac{{69}}{{91}}$$
D. $$\frac{{22}}{{91}}$$
Answer: Option C
Solution(By Examveda Team)
Choosing 4 shirts means 1st shirt and 2nd and then 3rd and then 4th shirtAt least 1 red shirt means there can be 1, 2, 3 or 4 red shirts
So, Probability of choosing red = 1 - Probability of not choosing red
If we remove red shirts, then 15 - 4 red shirts = 11 shirts remain.
We have to choose 4 out of these 11
So Probability of choosing 4 shirts which are not red
$$\eqalign{ & = \frac{{11}}{{15}} \times \frac{{10}}{{14}} \times \frac{9}{{13}} \times \frac{8}{{12}} \cr & = \frac{{22}}{{91}} \cr} $$
∴ Probability of picking at least 1 red shirt
$$\eqalign{ & = 1 - \frac{{22}}{{91}} \cr & = \frac{{69}}{{91}} \cr} $$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
Join The Discussion