A certain appliance uses 350 W. If it is allowed to run continuously for 24 days, how many kilowatt-hours of energy does it consume?
A. 20.16 kWh
B. 201.6 kWh
C. 2.01 kWh
D. 8.4 kWh
Answer: Option B
This Question Belongs to Electrical Engineering >> Energy And Power
Total kWH = power * time.
= 350 (watt) *24 (hour) *24 (days),
= 201600 watt hour,
= 201.6 kWH.