A certain number of student from school X appeared in an examination and 30% student failed. 150% more students than more from school X, appeared in the same examination from school Y, If 80% of the total number of students who appeared from X and Y passed, then what is the percentage of student who failed from Y?

Solution(By Examveda Team)

Calculation:
30% of the students from school X failed
Let the number of students from school X be 100
⇒ Number of students who failed = 30
⇒ Number of students who passed = (100 - 30) = 70
According to the question,
150% more students than school X, appeared in the examination from school Y
Number of students from school Y = $$100 + \left( {100 \times \frac{{150}}{{100}}} \right)$$
⇒ Number of students from school Y = 250
Again, according to the question,
80% of the total number of students from X and Y passed
Total students from school X and Y = 100 + 250 = 350
⇒ Total number of students who passed = $$350 \times \frac{{80}}{{100}}$$
⇒ Total number of students who passed = 280
Now,
Number of students who passed from school Y = 280 - 70
⇒ Number of students who passed from school Y = 210
Number of students who failed from school Y = 250 - 210
⇒ Number of students who failed from school Y = 40
Percentage of students who failed from Y = $$\frac{{40}}{{250}} \times 100$$
⇒ Percentage of students who failed from Y = 16%
∴ 16% of students failed from school Y.