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A complete $$\frac{7}{{10}}$$ of a work in 15 days, then he completed the remaining work with the help of B in 4 days. In how many day A and B can complete entire work together?

A. $$10\frac{1}{2}\,\,{\text{days}}$$

B. $$12\frac{2}{3}\,\,{\text{days}}$$

C. $$13\frac{1}{3}\,\,{\text{days}}$$

D. $$8\frac{1}{4}\,\,{\text{days}}$$

Answer: Option C

Solution(By Examveda Team)

$$\frac{7}{{10}}$$ part of work has been completed by A in 15 days. Then,
Rest work = 1 - $$\frac{7}{{10}}$$ = $$\frac{3}{{10}}$$ part
Given, That $$\frac{3}{{10}}$$ part of the work is completed by A and B together in 4 days. Means,
(A + B) completed the $$\frac{3}{{10}}$$ of work in 4 days
So, (A + B)'s 1 day's work = $$\frac{3}{{10 \times 4}}$$  = $$\frac{3}{{40}}$$
Hence,
(A + B) can complete the work in $$\frac{{40}}{3}$$ = $$13\frac{1}{3}$$ days

This Question Belongs to Arithmetic Ability >> Time And Work

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Comments ( 1 )

  1. Harjinderpal Singh
    Harjinderpal Singh :
    1 year ago

    Sol
    A×7/10=15
    A=150/7
    Remaining work 1-7/10=3/10
    (A+B)3/10=4
    A+B =40/3
    AS WE KNOW IF THERE IS 7/10 THEN 7 IS COMPLETED WORK AND 10 IS COMPLETE WORK
    LCM =COMPLETE WORK
    NOW FIND THERE CAPACITY
    A = 150/7 LCM IS 10 THATS WHY 10/150/7= 7/15
    A= 7/15
    A+B = 40/3 LCM IS 10 THEREFORE 10/40/3=3/4
    CAPACITY OF A+ B = 3/4
    NOW WE FIND CAPACITY OF ONLY B.
    SO
    B =3/4 -7/15 =17/60
    CAPACITY OF A+ B = 7/15+17/60
    A+B = 45/60
    TOTAL WORK = 10
    10/A+B
    10/45/60
    10×60/45= 40/3
    40/3 = 13.33333

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