A constant current signal across a parallel RLC circuits gives an output of 1.4v at the signal frequency of 3.89KHZ and 4.1KHZ. At the frequency of 4KHZ, the output voltage will be
A. 1 v
B. 2 v
C. 1.4 v
D. 2.8 v
Answer: Option B
Solution (By Examveda Team)
A constant current signal across a parallel RLC circuit gives an output of 1.4v at the signal frequencies of 3.89kHz and 4.1kHz. This indicates that the circuit is operating near its resonant frequency.At resonance, the impedance of the parallel RLC circuit is maximum, leading to a maximum voltage across it for a given current. In this case, the output voltage is 1.4v at frequencies close to resonance.
As we move further away from the resonant frequency, the impedance decreases, and consequently, the output voltage also decreases.
Therefore, at 4kHz, which is closer to the resonant frequency than 3.89kHz or 4.1kHz, the output voltage will be **slightly higher** than 1.4v.
Among the given options, Option B: 2v is the closest to this expected value.
This Question Belongs to Electronics And Communications Engineering >> Analog Electronics
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Comments (7)
The action of JFET in its equivalent circuit can best be represented as a
A. Current controlled Current source
B. Current controlled voltage source
C. Voltage controlled voltage source
D. Voltage controlled current source
In a p+n junction diode under reverse bias, the magnitude of electric field is maximum at
A. The edge of the depletion region on the p-side
B. The edge of the depletion region on the n-side
C. The p+n junction
D. The center of the depletion region on the n-side
To prevent a DC return between source and load, it is necessary to use
A. Resistor between source and load
B. Inductor between source and load
C. Capacitor between source and load
D. Either A or B
Kindly suggest a valid formula for this
How????
1.4 volts are given on both sides of peak, so at peak, the voltages should be slightly more than the given.
so v>1.4.
I think 2.8 is double and not possible under the condition so 2v is correct.
explain
6 db point drop in both side in terms of voltage so it must be 2.8 volts
Why
how