A constant current signal across a parallel RLC circuits gives an output of 1.4v at the signal frequency of 3.89KHZ and 4.1KHZ. At the frequency of 4KHZ, the output voltage will be
A. 1 v
B. 2 v
C. 1.4 v
D. 2.8 v
Answer: Option B
Solution (By Examveda Team)
A constant current signal across a parallel RLC circuit gives an output of 1.4v at the signal frequencies of 3.89kHz and 4.1kHz. This indicates that the circuit is operating near its resonant frequency.At resonance, the impedance of the parallel RLC circuit is maximum, leading to a maximum voltage across it for a given current. In this case, the output voltage is 1.4v at frequencies close to resonance.
As we move further away from the resonant frequency, the impedance decreases, and consequently, the output voltage also decreases.
Therefore, at 4kHz, which is closer to the resonant frequency than 3.89kHz or 4.1kHz, the output voltage will be **slightly higher** than 1.4v.
Among the given options, Option B: 2v is the closest to this expected value.
This Question Belongs to Electronics And Communications Engineering >> Analog Electronics
Kindly suggest a valid formula for this
How????
1.4 volts are given on both sides of peak, so at peak, the voltages should be slightly more than the given.
so v>1.4.
I think 2.8 is double and not possible under the condition so 2v is correct.
explain
6 db point drop in both side in terms of voltage so it must be 2.8 volts
Why
how