A contractor undertook to finish a work in 92 days and employed 110 men. After 48 days, he found that he had already done $$\frac{3}{5}$$ part of the work, the number of men he can withdraw so that his work may still be finished in time is ?

Let 'n' number of men can be withdrawn
$$\eqalign{ & \frac{{\left( {{{110}_{{\text{men}}}} \times {{48}_{{\text{days}}}}} \right)}}{{\frac{3}{5}{\text{work}}}} = \frac{{\left( {110 - {\text{n}}} \right) \times 44}}{{\frac{2}{5}{\text{work}}}} \cr & \Rightarrow 110 \times 16 = \left( {110 - {\text{n}}} \right) \times 22 \cr & \Rightarrow 160 = \left( {110 - {\text{n}}} \right) \times 2 \cr & \Rightarrow {\text{n}} = 30 \cr} $$