A dice is rolled twice. What is the probability of getting sum 9?
A. $$\frac{{2}}{{3}}$$
B. $$\frac{{1}}{{3}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{3}}{{9}}$$
Answer: Option C
Solution(By Examveda Team)
Possible event = 6 × 6 = 36Favourable outcomes = {(3, 6), {4, 5}, {5, 4}, (6, 3)}
∴ Probability
$$\eqalign{ & = \frac{{{\text{Favourable}}}}{{{\text{total}}}} \cr & = \frac{4}{{36}} \cr & = \frac{1}{9} \cr} $$
This Question Belongs to Arithmetic Ability >> Probability
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
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