A does half as much work as B in one -sixth of the time.If together they take 10 days to complete a work, how much time shall B take to do it alone?
A. 13.33 days
B. 20 days
C. 30 days
D. 40 days
Answer: Option D
Solution(By Examveda Team)
To do half of the work in one sixth of the time means A is 3 times as efficient as B. To understand this point just think if same work would have been done in one sixth of the time then A would have been six times as efficient as B. Now they together complete the work in 10 days.B is working with someone who is 3 times as efficient as himself.
That means 4 people of B's efficiency finished the work in 10 days.
So B alone would have done it in 40 days.
A alone would have taken one third of this time. Alternatively, Given, $${\text{A}} \times \frac{1}{6} = {\text{B}} \times \frac{1}{2}$$ So, A = 3B Now, Given they together complete the work in 10 days So, One Day''s work of, (A + B) = $$\frac{{100}}{{10}}$$ = 10% (3B + B) = 10% 4B = 10% So, one day work of B = $$\frac{{10}}{4}$$ = 2.5% So, B can complete 100% work in = $$\frac{100}{2.5}$$ = 40 days
Related Questions on Time and Work
A. 18 days
B. 24 days
C. 30 days
D. 40 days
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