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A five-digit number is formed by using digits 1, 2, 3, 4 and 5 without repetition. What is the probability that the number is divisible by 4?

A. $$\frac{{1}}{{5}}$$

B. $$\frac{{5}}{{6}}$$

C. $$\frac{{4}}{{5}}$$

D. None of these

Answer: Option A

Solution(By Examveda Team)

A number divisible by 4 formed using the digits 1, 2, 3, 4 and 5 has to have the last two digits 12 or 24 or 32 or 52.
In each of these cases, the five digits number can be formed using the remaining 3 digits in 3! = 6 ways.
A number divisible by 4 can be formed in 6 × 4 = 24 ways.
Total number that can be formed using the digits 1, 2, 3, 4 and 5 without repetition
= 5! = 120
Required probability,
$$\eqalign{ & = \frac{{24}}{{120}} \cr & = \frac{1}{5} \cr} $$

This Question Belongs to Arithmetic Ability >> Probability

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