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A flywheel on a motor goes from rest to 1000 rpm in 6 sec. The number of revolutions made is nearly equal to

A. 25

B. 50

C. 100

D. 250

Answer: Option B


This Question Belongs to Civil Engineering >> Strength Of Materials

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Comments ( 6 )

  1. Akshay Jaiswal
    Akshay Jaiswal :
    3 years ago

    It must be 100

  2. Riju Chakraborty
    Riju Chakraborty :
    4 years ago

    Intial angular velocity , ω₀ = 0 [because flywheel moves from rest ]
    final angular velocity, ω = 1000 rpm = 1000/60 rev/sec
    Time taken , t = 6 sec

    We know, the formula,
    ω = ω₀ + αt
    Where α is angular acceleration.
    1000/60 = 0 + α6
    α = 1000/360 = 100/36 = 25/9 rev/s²

    Now, use formula
    θ = ω₀t + 1/2αt²
    = 0 + 1/2 × 25/9 × (6)²
    = 1/2 × 25/9 × 36
    = 1/2 × 25 × 4
    = 50 rev

    Hence , number of revolution =50

  3. Gourab Bera
    Gourab Bera :
    5 years ago

    1000*6/60 = 100 will be the answer

  4. Uddhav Bulbule
    Uddhav Bulbule :
    5 years ago

    Will you give me the brief description of this question.

  5. Ishwarya K.V
    Ishwarya K.V :
    5 years ago

    Job

  6. Karanam Naveen
    Karanam Naveen :
    5 years ago

    How it is came 50??

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