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Examveda

A liquid decomposes by irreversible first order kinetics and the half life period of this reaction is 8 minutes. The time required for 75% conversion of the liquid will be __________ minutes.

A. 4

B. 8

C. 12

D. 16

Answer: Option D


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Comments ( 2 )

  1. Chintan Bhalerao
    Chintan Bhalerao :
    3 years ago

    For 1st order reaction half time is given by: T1/2 = 0.693/k
    here, it is given that T1/2 = 8 minutes so by using the equation calculate K.
    It is given that it is a first order reaction,
    So K = (1/T)*ln(CA0/CA) is the equation
    Assume CA0 as 1 and CA from the given question will be 0.25 (As 75% is converted)
    Why 0.25 because CA gives us the amount of reactant left after conversion.
    Put all the given values and calculate T you will get 16 minutes
    I hope you all got it.
    If anyone wants to study chemical engineering i give classes please mail me on
    chintanbhalerao3@gmail.com

  2. Habtamu Fekadu
    Habtamu Fekadu :
    3 years ago

    how? please show me clearly

Related Questions on Chemical Reaction Engineering

A first order gaseous phase reaction is catalysed by a non-porous solid. The kinetic rate constant and the external mass transfer co-efficients are k and $${{\text{k}}_{\text{g}}}$$ respectively. The effective rate constant (keff) is given by

A. $${{\text{k}}_{\text{e}}}{\text{ff}} = {\text{k}} + {{\text{k}}_{\text{g}}}$$

B. $${{\text{k}}_{\text{e}}}{\text{ff}} = \frac{{{\text{k}} + {{\text{k}}_{\text{g}}}}}{2}$$

C. $${{\text{k}}_{\text{e}}}{\text{ff}} = {\left( {{\text{k}}{{\text{k}}_{\text{g}}}} \right)^{\frac{1}{2}}}$$

D. $$\frac{1}{{{{\text{k}}_{\text{e}}}{\text{ff}}}} = \frac{1}{{\text{k}}} + \frac{1}{{{{\text{k}}_{\text{g}}}}}$$