A man has 'n' magical eggs whose average weight is 'k' gm. Each of the 'n' eggs produces 'n' eggs next day such that the average weight of 'n' eggs produced is same as that of the parental egg for each 'n' groups individually i.e. each egg produces 'n' eggs of next generation and average weight of all the 'n' eggs of next generation is same as the weight of the mother egg. This process is continued without any change in pattern. What is the total weight of all the eggs of rth generation, where the initial number of eggs with man are considered as the eggs of first generation.
A. rnk
B. rnk
C. nkr
D. nrk
E. None of these
Answer: Option D
Solution (By Examveda Team)
The weight is increasing in form of GP so the total weight of eggs in the end of rth will be nrk.Join The Discussion
Comments (1)
Related Questions on Average
A. 125 km/hr
B. 75 km/hr
C. 135 km/hr
D. 120 km/hr
Let's break this down step by step:
1. The man has 'n' eggs of the first generation, with an average weight of 'k' gm. The total weight of these eggs is 'n' x 'k' = 'nk' gm.
2. Each of these 'n' eggs produces 'n' eggs in the next generation, making a total of 'n' x 'n' = 'n^2' eggs in the second generation.
3. Since the average weight of the eggs produced by each parental egg is the same as the weight of the parental egg, the total weight of the eggs in the second generation is also 'nk' gm per group, making a total of 'n' x 'nk' = 'n^2k' gm for all 'n' groups.
4. This process continues for each subsequent generation, with the total weight of eggs in each generation being 'n' times the total weight of eggs in the previous generation.
5. Therefore, the total weight of eggs in the 'rth' generation is 'n^(r-1)' x 'nk' = 'n^r k' gm.
So, the total weight of all the eggs of the 'rth' generation is 'n^r k' gm.