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The average of the first five multiples of 9 is:
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& {\text{Required}}\,{\text{average}} \cr
& = {\frac{{{\text{total}}\,{\text{sum}}\,{\text{of}}\,{\text{multiple}}\,{\text{of}}\,9}}{5}} \cr
& = {\frac{{9 + 18 + 27 + 36 + 45}}{5}} \cr
& = 27 \cr} $$
Note that, average of 9 and 45 is also 27.
And average of 18 and 36 is also 27.
Note that, average of 9 and 45 is also 27.
And average of 18 and 36 is also 27.
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LoginAvg = 1st + Last / 2
(9+45)/2 = 27
RJ Champ
(9+45) / 2
= 54/2
=27
Avg= first term + last term /2
hence, 9+45/2=27
=27
=27