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The average of the first five multiples of 9 is:

A. 20

B. 27

C. 28

D. 30

Answer: Option B

Solution(By Examveda Team)

$$\eqalign{ & {\text{Required}}\,{\text{average}} \cr & = {\frac{{{\text{total}}\,{\text{sum}}\,{\text{of}}\,{\text{multiple}}\,{\text{of}}\,9}}{5}} \cr & = {\frac{{9 + 18 + 27 + 36 + 45}}{5}} \cr & = 27 \cr} $$
Note that, average of 9 and 45 is also 27.
And average of 18 and 36 is also 27.

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Comments ( 7 )

  1. Atif Rehman
    Atif Rehman :
    10 months ago

    9,18,27.36,45
    Avg = 1st + Last / 2
    (9+45)/2 = 27
    RJ Champ

  2. Bikash Bhattarai
    Bikash Bhattarai :
    11 months ago

    Ans = 9(1+2+3+4+5)/5

  3. FACTOM WORLD
    FACTOM WORLD :
    2 years ago

    (1st +last term) / 2
    (9+45) / 2
    = 54/2
    =27

  4. Nafeesh Haider
    Nafeesh Haider :
    2 years ago

    9(1,2,3,4,5)/5 = 9*5(5+1)/2/5 9*6/2

  5. Mohana Gowri
    Mohana Gowri :
    3 years ago

    Another method for this ,

    Avg= first term + last term /2
    hence, 9+45/2=27

  6. Santosh Kumar
    Santosh Kumar :
    4 years ago

    9×15/5=9×3
    =27

  7. Nvjddurrg Jgyureey
    Nvjddurrg Jgyureey :
    5 years ago

    9+45/2
    =27

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