ExamVeda
Login
Home
This question belongs to Arithmetic Ability Average
Average
?

The average of the first five multiples of 9 is:

Answer & Solution
Correct Answer: Option B
$$\eqalign{ & {\text{Required}}\,{\text{average}} \cr & = {\frac{{{\text{total}}\,{\text{sum}}\,{\text{of}}\,{\text{multiple}}\,{\text{of}}\,9}}{5}} \cr & = {\frac{{9 + 18 + 27 + 36 + 45}}{5}} \cr & = 27 \cr} $$
Note that, average of 9 and 45 is also 27.
And average of 18 and 36 is also 27.
Examveda
Question posted by Examveda
Community

Join the Discussion

9 Comments
Muhammad Abrar
Muhammad Abrar 3 years ago
nice
Sushil Kumar
Sushil Kumar 3 years ago
(Fist9+last 45)/2=27
Atif Rehman
Atif Rehman 5 years ago
9,18,27.36,45
Avg = 1st + Last / 2
(9+45)/2 = 27
RJ Champ
Bikash Bhattarai
Bikash Bhattarai 5 years ago
Ans = 9(1+2+3+4+5)/5
FACTOM WORLD
FACTOM WORLD 5 years ago
(1st +last term) / 2
(9+45) / 2
= 54/2
=27
Nafeesh Haider
Nafeesh Haider 6 years ago
9(1,2,3,4,5)/5 = 9*5(5+1)/2/5 9*6/2
Mohana Gowri
Mohana Gowri 6 years ago
Another method for this ,

Avg= first term + last term /2
hence, 9+45/2=27
Santosh Kumar
Santosh Kumar 7 years ago
9×15/5=9×3
=27
Nvjddurrg Jgyureey
Nvjddurrg Jgyureey 8 years ago
9+45/2
=27