A mass m is connected on either side with a spring each of spring constants k1 and k2. The free ends of springs are tied to rigid supports. The displacement of the mass is x from equilibrium position.
Which one of the following is true?
A. The force acting on the mass is $${\left( {{k_1}{k_2}} \right)^{\frac{1}{2}}}x$$
B. The angular momentum of the mass is zero about the equilibrium point and its Lagrangian $$\frac{1}{2}m{{\dot x}^2} - \frac{1}{2}\left( {{k_1} + {k_2}} \right){x^2}$$
C. The total energy of the system is $$\frac{1}{2}m{{\dot x}^2}$$
D. The angular momentum of the mass is $$mx\dot x$$ and Lagrangian of system is $$\frac{m}{2}\dot x + \frac{1}{2}\left( {{k_1} + {k_2}} \right){x^2}$$
Answer: Option B
This Question Belongs to Engineering Physics >> Classical Mechanics
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