A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 8.00 a.m., at what time will he first touch a flag at 120 feet from the ground?
A. 4 p.m.
B. 5 p.m.
C. 6 p.m.
D. None of these
Answer: Option C
Solution(By Examveda Team)
Net ascent of the monkey in 1 hour = (30 - 20) feet = 10 feet.So, the monkey ascends 90 feet in 9 hours i.e. till 5 p.m.
Clearly, in the next 1 hour i.e. till 6 p.m. the monkey ascends remaining 30 feet to touch the flag.
This Question Belongs to Competitive Reasoning >> Arithmetic Reasoning
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The answer should be 5pm..so update the option c to b...
The question seems unclear as they clearly mentioned the monkey ascends 30 feet at the beginning at every hour and then falls back 20 feet for the remainder of the hour. Which means at 4:59 it would be at 90 feet and beginning of the 5:00 pm stretch it would be at 120 feet. By the time 5:59 comes it would be at 100 feet. So.... My confusion is there.