A number when divided by three consecutive numbers 9, 11, 13 leaves the remainders 8, 9 and 8 respectively. If the order of divisors is reversed, the remainders will be :
A. 10, 8, 9
B. 10, 1, 6
C. 8, 9, 8
D. 9, 8, 8
Answer: Option B
Solution(By Examveda Team)
z = 13 × 1 + 8 = 21
y = 11 × z + 9 = 11 × 21 + 9 = 240
x = 9 × y + 8 = 9 × 240 + 8 = 2168
Now, when order of divisor is reversed, we have :
∴ Respective remainders are 10, 1 and 6
This Question Belongs to Arithmetic Ability >> Number System
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