A number X is chosen at random from the numbers -3, -2, -1, 0, 1, 2, 3. What is the probability that $$|X| < 2$$
A. $$\frac{{5}}{{7}}$$
B. $$\frac{{3}}{{7}}$$
C. $$\frac{{3}}{{5}}$$
D. $$\frac{{1}}{{3}}$$
Answer: Option B
Solution(By Examveda Team)
$$|X|$$ can take 7 values.To get $$|X| < 2$$ (i.e., -2 < x < + 2) take X = {-1, 0, 1}
$$P\left( {|X| < 2} \right) = $$ $$\frac{{{\text{Favourable Cases}}}}{{{\text{Total Cases}}}}$$
$$ = \frac{3}{7}$$
Related Questions on Probability
A. $$\frac{{1}}{{2}}$$
B. $$\frac{{2}}{{5}}$$
C. $$\frac{{8}}{{15}}$$
D. $$\frac{{9}}{{20}}$$
A. $$\frac{{10}}{{21}}$$
B. $$\frac{{11}}{{21}}$$
C. $$\frac{{2}}{{7}}$$
D. $$\frac{{5}}{{7}}$$
A. $$\frac{{1}}{{3}}$$
B. $$\frac{{3}}{{4}}$$
C. $$\frac{{7}}{{19}}$$
D. $$\frac{{8}}{{21}}$$
E. $$\frac{{9}}{{21}}$$
What is the probability of getting a sum 9 from two throws of a dice?
A. $$\frac{{1}}{{6}}$$
B. $$\frac{{1}}{{8}}$$
C. $$\frac{{1}}{{9}}$$
D. $$\frac{{1}}{{12}}$$
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