A particle A of diameter 10 microns settles in an oil of specific gravity 0.9 and viscosity 10 poise under Stoke's law. A particle B with diameter 20 microns settling in the same oil will have a settling velocity
A. Same as that of A
B. One fourth as that of A
C. Twice as that of A
D. Four times as that of A
Answer: Option B
From stokes law,
Ut=(g*Dp^2*(Rho p-Rho))/18mue
“Ut” directly proportional to “Dp” then
=> (Ut)a / (Ut)b = (Dp^2)a / (Dp^2)b
=> (Ut)a / (Ut)b = (10^2) / (20^2)
Therefore; (Ut)a / (Ut)b = 1/4