Solution (By Examveda Team)
$$\eqalign{
& {\text{Interest at the end of }}{{\text{1}}^{{\text{st}}}}{\text{ year}} \cr
& = \frac{{1,00,000 \times 10}}{{100}} \cr
& = 10,000 \cr
& {\text{Paid amount}} = 10,000 \cr
& {\text{Rest amount}} \cr
& = 1,10,000 - 10,000 \cr
& = 1,00,000 \cr
& {\text{Interest for }}{{\text{2}}^{{\text{nd}}}}{\text{ year}} = 10,000 \cr
& {\text{Amount paid}} = 20,000 \cr
& {\text{Remaining amount}} \cr
& = 1,10,000 - 20,000 \cr
& = 90,000 \cr
& {\text{Interest for }}{{\text{3}}^{{\text{rd}}}}{\text{ year}} = 9,000 \cr
& {\text{Amount paid}} = 30,000 \cr
& {\text{Remaining amount}} \cr
& = 99,000 - 30,000 \cr
& = 69,000 \cr
& {\text{Interest for }}{{\text{4}}^{{\text{th}}}}{\text{ year}} = 6,900 \cr
& {\text{Amount paid}} = 40,000 \cr
& {\text{Remaining amount}} \cr
& = 75,900 - 40,000 \cr
& = 35,900 \cr
& {\text{Interest for }}{{\text{5}}^{{\text{th}}}}{\text{ year}} \cr
& = \frac{{35,900 \times 10}}{{100}} \cr
& = 3,590 \cr
& {\text{Amount paid at the end of }}{{\text{5}}^{{\text{th}}}}{\text{ year}} \cr
& = 35,900 + 3,590 \cr
& = 39,490 \cr} $$
But this is wrong .You are using concept of Compound Interest. You must have to subtract installments from principal. For getting the right answer you are totally breaking the rule ..Wow Clap for your hardwork !! 🤞