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A person divided Rs. 10800 among his three sons in the ratio 3 : 4 : 5. Second son kept Rs. 1000 for himself, gave Rs. 600 to his wife and divided the remaining money among his two daughters in the ratio 11 : 9. Then one of his daughters received.

A. Rs. 1000

B. Rs. 1050

C. Rs. 1100

D. Rs. 1150

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & {\text{Second son's share}} \cr & = {\text{Rs}}{\text{.}}\left( {10800 \times \frac{4}{{12}}} \right) \cr & = {\text{Rs}}{\text{. }}3600 \cr} $$
Money distributed between the two daughters
= Rs. [3600 - (1000 + 600)]
= Rs. 2000
$$\eqalign{ & {\text{First daughter's share}} \cr & = {\text{Rs}}{\text{.}}\left( {2000 \times \frac{{11}}{{20}}} \right) \cr & = {\text{Rs}}.1100. \cr & {\text{Second daughter's share}} \cr & = {\text{Rs}}{\text{.}}\left( {2000 \times \frac{9}{{20}}} \right) \cr & = {\text{Rs}}{\text{. 9}}00 \cr} $$

This Question Belongs to Arithmetic Ability >> Ratio

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