A pipe can fill a tank with water in 3 hours. Due to leakage in bottom, it takes $$3\frac{1}{2}$$ hours to fill it. In what time the leak will empty the completely filled tank?
A. 12 hours
B. 21 hours
C. $$6\frac{1}{2}$$ hours
D. $$10\frac{1}{2}$$ hours
Answer: Option B
Solution (By Examveda Team)
Let the total capacity of tank is 21 unitsA's efficiency is 7 units/hr
A's efficiency after leakage 6 units/hr
leakage efficiency = 7 - 6 = 1 unit/hr
leakage will empty the filled tank
$$\frac{{{\text{Total Capacity}}}}{{{\text{Efficiency }}}} = \frac{{21}}{1}$$
= 21hours
1stly
3h=1part
1h=1/3part
2ndly
7/2h=1part
1h=2/7part
now
1/3-2/7=7-6/21=1/21part
so
1/21part=1h
1part=21h