Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:

A. $$1\frac{{13}}{{17}}$$ hours

B. $$2\frac{8}{{11}}$$ hours

C. $$3\frac{9}{{17}}$$ hours

D. $$4\frac{1}{2}$$ hours

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & {\text{Net}}\,{\text{part}}\,{\text{filled}}\,{\text{in}}\,{\text{1}}\,{\text{hour}} \cr & = {\frac{1}{5} + \frac{1}{6} - \frac{1}{{12}}} = \frac{{17}}{{60}} \cr & \therefore {\text{The}}\,{\text{tank}}\,{\text{will}}\,{\text{be}}\,{\text{full}}\,{\text{in}}\,\frac{{60}}{{17}}\,{\text{hours}} \cr & i.e.,\,3\frac{9}{{17}}\,{\text{hours}} \cr} $$

This Question Belongs to Arithmetic Ability >> Pipes And Cistern

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Comments ( 1 )

  1. Nilesh Barke
    Nilesh Barke :
    3 years ago

    It should be 3+9

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