A pipe can fill a tank with water in 3 hours. Due to leakage in bottom, it takes $$3\frac{1}{2}$$ hours to fill it. In what time the leak will empty the completely filled tank?
A. 12 hours
B. 21 hours
C. $$6\frac{1}{2}$$ hours
D. $$10\frac{1}{2}$$ hours
Answer: Option B
Solution(By Examveda Team)
Let the total capacity of tank is 21 unitsA's efficiency is 7 units/hr
A's efficiency after leakage 6 units/hr
leakage efficiency = 7 - 6 = 1 unit/hr
leakage will empty the filled tank
$$\frac{{{\text{Total Capacity}}}}{{{\text{Efficiency }}}} = \frac{{21}}{1}$$
= 21hours
This Question Belongs to Arithmetic Ability >> Pipes And Cistern
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Related Questions on Pipes and Cistern
A. $$\frac{5}{{11}}$$
B. $$\frac{6}{{11}}$$
C. $$\frac{7}{{11}}$$
D. $$\frac{8}{{11}}$$
A. $$1\frac{{13}}{{17}}$$ hours
B. $$2\frac{8}{{11}}$$ hours
C. $$3\frac{9}{{17}}$$ hours
D. $$4\frac{1}{2}$$ hours
A. $$4\frac{1}{3}$$ hours
B. 7 hours
C. 8 hours
D. 14 hours
1stly
3h=1part
1h=1/3part
2ndly
7/2h=1part
1h=2/7part
now
1/3-2/7=7-6/21=1/21part
so
1/21part=1h
1part=21h