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A planet moves around the sun in an elliptical orbit with semi-major axis a and time period T. T is proportional to
Answer & Solution
Correct Answer:
Option
D
According to Kepler's third law, the square of the period of revolution (T) of a planet around the sun is proportional to the cube of the semi-major axis (a) of its elliptical orbit.
Thus, T2∝a3
Taking the square root on both sides, we get:
$$T∝ {{\text{a}}^{\frac{3}{2}}}$$
Hence, the time period (T) is proportional to $${{\text{a}}^{\frac{3}{2}}}$$ which corresponds to Option D.
Thus, T2∝a3
Taking the square root on both sides, we get:
$$T∝ {{\text{a}}^{\frac{3}{2}}}$$
Hence, the time period (T) is proportional to $${{\text{a}}^{\frac{3}{2}}}$$ which corresponds to Option D.

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