A resistor is connected across a 50 V source. What is the current in the resistor if the color code is red, orange and silver?
A. 2 mA
B. 2.27 mA
C. 217 mA
D. 21.7 mA
Answer: Option C
Solution (By Examveda Team)
Okay, let's break down this problem step-by-step!First, we need to figure out the resistance using the color code: red, orange, and silver.
* Red = 2
* Orange = 3
* Silver = 10% tolerance (we'll ignore tolerance for calculating resistance).
So, the resistor value is 23 ohms.
Now, we can use Ohm's Law which is: Voltage (V) = Current (I) * Resistance (R) or V = IR.
We know the voltage (V) is 50 V and the resistance (R) is 23 ohms. We want to find the current (I).
We can rearrange Ohm's Law to solve for current: I = V / R
Plug in the values: I = 50 V / 23 ohms = 2.17 Amperes(A).
Since the options are in milliamperes (mA), we need to convert Amperes to milliamperes. Remember 1 A = 1000 mA.
So, 2.17 A * 1000 mA/A = 217 mA (approximately).
Option C: 217 mA
Answer should be 217 Amp....by calculation...
Red=2
Orange=3
Silver=10^-2
Tolarance=no colour=20%
R=23/100
=.23ohm
I=V/R
=50/.23
=217 ohm
the resistor code is BBROYGBVGW
BLACK = 0
BROWN = 1
RED = 2
ORANGE = 3
YELLOW = 4
GREEN = 5
BLUE = 6
VIOLET = 7
GRAY = 8
WHITE = 9
SILVER IS 10 PERCENT TOLERANCE, GOLD IS 5 PERCENT TOLERANCE
YOU HAVE 23 X 10^3 OR 23 kOHMS. E = IR, I = E/R = 50/23kOHMS = 2.17 mA(10^-3)
pls solution this question