What is the approximate filament resistance of a light bulb if it operates from a 110 V source and 0.6 A of current is flowing?
A. 183 Ω
B. 18.3 Ω
C. 66 Ω
D. 6.6 Ω
Answer: Option A
This Question Belongs to Electrical Engineering >> Ohms Law
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Related Questions on Ohms Law
How much current is produced by a voltage of 18 kV across a 15 kΩ resistance?
A. 1.2 A
B. 12 A
C. 120 mA
D. 12 mA
A. 183 Ω
B. 18.3 Ω
C. 66 Ω
D. 6.6 Ω
To find the filament resistance of the light bulb, we can use Ohm's Law, which states:
[
R = frac{V}{I}
]
Where:
- ( R ) is the resistance,
- ( V ) is the voltage,
- ( I ) is the current.
### Given:
- ( V = 110 , V )
- ( I = 0.6 , A )
### Step 1: Calculate the resistance:
[
R = frac{110 , V}{0.6 , A} = frac{110}{0.6} approx 183.33 , Omega
]
### Conclusion:
Thus, the approximate filament resistance of the light bulb is:
**A. 183 Ω.**
How it is?
How it is..??
Kaskay