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This question belongs to Electrical Engineering Ohms Law
Ohms Law
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A resistor is connected across a 50 V source. What is the current in the resistor if the color code is red, orange and silver?

Answer & Solution
Correct Answer: Option C
Okay, let's break down this problem step-by-step!

First, we need to figure out the resistance using the color code: red, orange, and silver.

* Red = 2
* Orange = 3
* Silver = 10% tolerance (we'll ignore tolerance for calculating resistance).

So, the resistor value is 23 ohms.

Now, we can use Ohm's Law which is: Voltage (V) = Current (I) * Resistance (R) or V = IR.

We know the voltage (V) is 50 V and the resistance (R) is 23 ohms. We want to find the current (I).

We can rearrange Ohm's Law to solve for current: I = V / R

Plug in the values: I = 50 V / 23 ohms = 2.17 Amperes(A).

Since the options are in milliamperes (mA), we need to convert Amperes to milliamperes. Remember 1 A = 1000 mA.

So, 2.17 A * 1000 mA/A = 217 mA (approximately).

Option C: 217 mA
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4 Comments
Jinal Tandel
Jinal Tandel 1 year ago
Answer should be 217 Amp....by calculation...
Ameer Ali
Ameer Ali 6 years ago
Red=2
Orange=3
Silver=10^-2
Tolarance=no colour=20%
R=23/100
=.23ohm
I=V/R
=50/.23
=217 ohm
Ron Crawford
Ron Crawford 7 years ago
the resistor code is BBROYGBVGW
BLACK = 0
BROWN = 1
RED = 2
ORANGE = 3
YELLOW = 4
GREEN = 5
BLUE = 6
VIOLET = 7
GRAY = 8
WHITE = 9
SILVER IS 10 PERCENT TOLERANCE, GOLD IS 5 PERCENT TOLERANCE
YOU HAVE 23 X 10^3 OR 23 kOHMS. E = IR, I = E/R = 50/23kOHMS = 2.17 mA(10^-3)
Ramgopal Singh
Ramgopal Singh 8 years ago
pls solution this question