A reversible engine has ideal thermal efficiency of 30%. When it is used as a refrigerating machine with all other conditions unchanged, the coefficient of performance will be
A. 1.33
B. 2.33
C. 3.33
D. 4.33
Answer: Option B
Solution (By Examveda Team)
C.O.P. is reciprocal of efficiency of heat engine.C.O.P. = $$\frac{1}{{0.3}}$$
= 3.33 = C.O.P. of heat engine.
Now,
C.O.P. of refrigerator = C.O.P. of heat engine - 1
= 3.33 - 1
= 2.33.
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