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Examveda

A reversible engine has ideal thermal efficiency of 30%. When it is used as a refrigerating machine with all other conditions unchanged, the coefficient of performance will be

A. 1.33

B. 2.33

C. 3.33

D. 4.33

Answer: Option B

Solution(By Examveda Team)

C.O.P. is reciprocal of efficiency of heat engine.
C.O.P. = $$\frac{1}{{0.3}}$$
= 3.33 = C.O.P. of heat engine.
Now,
C.O.P. of refrigerator = C.O.P. of heat engine - 1
= 3.33 - 1
= 2.33.

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Related Questions on Refrigeration and Air Conditioning

Nusselt number (NN) is given by

A. $${{\text{N}}_{\text{N}}} = \frac{{{\text{h}}l}}{{\text{k}}}$$

B. $${{\text{N}}_{\text{N}}} = \frac{{\mu {{\text{c}}_{\text{p}}}}}{{\text{k}}}$$

C. $${{\text{N}}_{\text{N}}} = \frac{{\rho {\text{V}}l}}{\mu }$$

D. $${{\text{N}}_{\text{N}}} = \frac{{{{\text{V}}^2}}}{{{\text{t}}{{\text{c}}_{\text{p}}}}}$$