A rod of length L0 makes an angle θ0 with the Y-axis in its rest frame while the rest frame moves to the right along the X-axis with relativistic speed v with respect to lab frame. If $$\gamma = {\left( {1 - \frac{{{v^2}}}{{{c^2}}}} \right)^{ - \frac{1}{2}}},$$ the angle in the lab frame is
A. $$\theta = {\tan ^{ - 1}}\left( {\gamma \tan {\theta _0}} \right)$$
B. $$\theta = {\tan ^{ - 1}}\left( {\gamma \cot {\theta _0}} \right)$$
C. $$\theta = {\tan ^{ - 1}}\left( {\frac{{\tan {\theta _0}}}{\gamma }} \right)$$
D. $$\theta = {\tan ^{ - 1}}\left( {\frac{{\cot {\theta _0}}}{\gamma }} \right)$$
Answer: Option B
This Question Belongs to Engineering Physics >> Classical Mechanics
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